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vecP = (2hati - 2hatj +hatk) , then fin...

` vecP = (2hati - 2hatj +hatk) ` , then find `|vecP|`

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The correct Answer is:
a,c,d
`veca=1/3(2hati-2hatj+hatk)`
`|veca|^(2)=1/9(4+4+1)=1or |veca|=1`
Let `vecb = 2hati - 4hatj + 3hatj`, then
` cos theta = (veca.vecb)/(|veca||vecb|) = 5/sqrt29 Rightarrow vecc ||veca`
Let `vecd = 3hati + 2hatj + 2hatk, " then " veca. vecd =0 Rightarrrow veca bot vecd`
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