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In a triangle A B CifB C=(3)^(1/2) and A...

In a triangle `A B CifB C=(3)^(1/2) and A C=2,` then what is the maximum possible value of angle `A ?`

Text Solution

Verified by Experts

Using Sine Rule, `(1)/(sin A) = (2)/(sin B)`
or `sin A = (sin B)/(2)`

`rArr` Maximum valur of `sin A " is " (1)/(2)`
Hence, `A = (pi)/(6)`
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