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If A=30^0, a=7,and b=8 in A B C , then ...

If `A=30^0, a=7,and b=8` in ` A B C ,` then find the number of triangles that can be constructed.

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We have `(a)/(sin A) = (b)/(sin B)`
or `sinB = (b sin A)/(a) = (8 sin 30^(@))/(7) = (4)/(7)`
Thus, we have, `b gt a gt b sin A`
Hence, angle B has two value given by `sin B = 4//7`
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CENGAGE PUBLICATION-PROPERTIES AND SOLUTIONS OF TRIANGLE-Illustration
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