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If circumradius of triangle ABC is 4 cm,...

If circumradius of triangle ABC is 4 cm, then prove that sum of perpendicular distances from circumcentre to the sides of triangle cannot exceed 6 cm

Text Solution

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Given that R = 4 cm
Sum of perpendicular distances from circumcentre to the sides of triangle,
`S = R (cos A + cos B + cosC)`
`= 4 (cos A + cos B + cos C) le 4 (3//2)`
Thus, S cannot exceed 6
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