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In acute angled triangle A B C ,A D is t...

In acute angled triangle `A B C ,A D` is the altitude. Circle drawn with `A D` as its diameter cuts `A Ba n dA Ca tPa n dQ ,` respectively. Length of `P Q` is equal to `/(2R)` (b) `(a b c)/(4R^2)` `2RsinAsinBsinC` (d) Δ`/R`

A

`(Delta)/(2R)`

B

`(abc)/(4R^(2))`

C

`2R sin A sin B sin C`

D

`(Delta)/(R)`

Text Solution

Verified by Experts

The correct Answer is:
C, D

`AD = c sin B`
Let R' be circumradius of `DeltaAPQ`.
Using sine rule in triangle APQ, we get
`(PQ)/(sin A) = 2R' = AD = c sin B`
`rArr PQ = c sin B sin A = c (b)/(2R) sin A = (Delta)/(R)`
Also, PQ `= c sin B sin A`
`=2R sin C sin B sin A`
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