Consider a triangle `A B C`
and let `a , ba n dc`
denote the lengths of the sides opposite to vertices `A , B ,a n dC`
, respectively. Suppose `a=6,b=10 ,`
and the area of triangle is `15sqrt(3)dot`
If `/_A C B`
is obtuse and if `r`
denotes the radius of the incircle of the triangle, then the value of `r^2`
is
Text Solution
Verified by Experts
The correct Answer is:
3
`Delta = (1)/(2) ab sin C rArr sin C = (2Delta)/(ab) = (2 xx 15 sqrt3)/(6 xx 10) = (sqrt3)/(2)` `rArr C = 120^(@)` `rArr c = sqrt(a^(2) + b^(2) - 2ab cos C)` `= sqrt(6^(2) + 10^(2) - 2 xx 6 xx 10 xx cos 120^(@)) = 14` Now `r = (Delta)/(s)` `rArr r^(2) = (225 xx 3)/(((6 + 10 + 14)/(2))^(2)) = 3`
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