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If det, (A-B) ne 0, A^(4)=B^(4), C^(3) A...

If det, `(A-B) ne 0, A^(4)=B^(4), C^(3) A=C^(3)B` and `B^(3)A=A^(3)B`, then find the value of det. `(A^(3)+B^(3)+C^(3))`.

A

`0`

B

`1`

C

`3|A|^(3)`

D

`6`

Text Solution

Verified by Experts

The correct Answer is:
A

`(a)` `(A^(3)+B^(3)+C^(3))(A-B)=A^(4)-A^(3)B+B^(3)A-B^(4)+C^(3)A-C^(3)B=0`
`implies|(A^(3)+B^(3)+C^(3))(A-B)|=0`
`implies|(A^(3)+B^(3)+C^(3))|=0`, since `|(A-B)|ne0`
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