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The probability that a dealer will sell ...

The probability that a dealer will sell at least `20TV` sets during a day is `0.45` and the probability that he will sell less than `24TV` sets is `0.74`. The probability that he will sell `20,21,22` or `23` TV sets during the day is

A

`0.19`

B

`0.29`

C

`0.333`

D

`0.81`

Text Solution

Verified by Experts

The correct Answer is:
A
`(a)` Let event `A to` dealer will sell at least `20TV` sets
and events `B to` dealer will sell less than `24TV` sets.
Now the event that dealer sells `20,21,22` or `23 TV` sets is `AnnB`
`:. P(AnnB)=P(A)+P(B)-P(AuuB)=0.45+0.74=0.19`
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