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If A(1), A(2),..,A(n) are any n events, ...

If `A_(1), A_(2),..,A_(n)` are any n events, then

A

`sum_(i=1)^(n)P(A_(i))=1`

B

`sumP(A_(i)) le 1` if `A_(1)`, A_(2),……,A_(n)` are disjoint

C

`sumP(A_(i)) ge 1` if `A_(1)`, A_(2),……,A_(n)` are exhaustive events

D

None of these

Text Solution

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The correct Answer is:
B, C
`(b,c)`
`(a)` is false since `A_(1),A_(2),………,A_(n)` may be overlapping.
`(b)` if `A_(1),A_(2),……,A_(n)` are disjoint and exhaustive both then `sumP(A_(i))=1` if they are only exclusive then `sumP(A_(i)) le 1`.
If exhaustive then `sumP(A_(i)) ge 1` (choice `( c)` follows)
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