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A man throws a die until he gets a numbe...

A man throws a die until he gets a number greater than `3`. The probability that he gets `5` in the last throw

A

`1//3`

B

`1//4`

C

`1//6`

D

`1//36`

Text Solution

Verified by Experts

The correct Answer is:
A

`(a)` At event `A` he gets a number greater than `3`
`:.P(A)=1//2`
At event `B` he gets `5` in last throw
`:.P(B)=1//6`
`:.` Required probability is
`P(E)=(1)/(6)+(1)/(2)*(1)/(6)+(1)/(2)*(1)/(2)*(1)/(6)+…..oo`
`=((1)/(6))/(1-(1)/(2))=(1)/(3)`
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