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For any events A and B. Given P(AuuB)=0....

For any events `A` and `B`. Given `P(AuuB)=0.6`, `P(A)=P(B)=0.4`, Then the value of `P[AnnB]` is

A

`1//3`

B

`1//2`

C

`1//4`

D

`1//5`

Text Solution

Verified by Experts

The correct Answer is:
D

`(d)` Let `P(A)=P(B)=p` (say)
`P(B//A)=(P(BnnA))/(P(A))`
`:.(0.8)p=P(BnnA)`………..`(i)`
`P(AuuB)=p+p-P(AnnB)`
`0.6=2p-p(0.8)=(1.2)p`
`:.p=(0.6)/(1.2)=(1)/(2)`
`:.P(A)=P(B)=(1)/(2)`
Now, `P[AnnbarB) uu (barAnnB)]`
`=P(A)+P(B)-2P(AnnB)`
`=1-2(0.8)(1)/(2)=0.2=(1)/(5)`
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