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The functions f(x), g(x) and h(x) sati...

The functions `f(x)`, `g(x)` and `h(x)` satiafy the relations, `f'(x) = g (x+1)` and `g'(x)= h (x-1)` then `f''(2x)=?`

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`f(-x)=(h_(1)(-x)-h_(1)(x))(h_(2)(-x)-h_(2)(x))…(h_(2n+1)(-x)-h_(2n+1)(x))`
` :. f(-x)=(-1)^(2n+1)f(x)=-f(x)`
or `f(x)+f(-x)=0`
So, f(x) is odd. Therefore,
`f(-200)=-f(200)=0`
So, f(x) is many-one.
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