The graph of the derivative f'(x) is given in the following figure.
(a) Find the interval in which f is increasing or decreasing.
(b) Find the values of x for which f has local maximum or minimum.
(c) Find the intervals in which f is concave upward or downward.
(c) Find the point of inflection.

Explanation

We have `f:R to [1,oo),f(x)=x^(2)-4x+5`
or `f(x) =(x-2)^ (2)+1.`
Graph of the function is as shown in the following figure.

Clearly f(x) is many-one function.
However, in the interval `(-oo,2] or [2,oo), f(x)` is one-one.
For ` f:(-oo,2] to [1,oo),y=(x-2)^(2) +1`
` :. (x-2)^(2)=y-1`
` implies x-2=sqrt(y-1)`
`implies x=2-sqrt(y-1)`
Thus `f^(-1):[1,oo) to (-oo,2],f^(-1)(x)=2-sqrt(x-1)`
For `f:[2,oo) to [1,oo),y=(x-2)^(2)+1`
`implies x=2 +sqrt(y-1)`
Thus ` f^(-1):[1,oo) to [2,oo),f^(-1)(x)=sqrt(x-1)+2`