Find the range of `f(x)=tan^(-1)sqrt((x^2-2x+2))`

Answer

`[pi//4,pi//2)`

Explanation

`f(x)=tan^(-1)(sqrt((x-1)^(2)+1))`
Now, `(x-1)^(2) +1 in [1,oo)`
or `tan^(-1)(sqrt((x-1)^(2)+1))in [(pi)/(4),(pi)/(2))`