Find the domain of the function `f(x)=(1)/(8{x}^(2)-6{x}+1).`

Answer

`R-{x:x=n+1//4,n+1//2,n in Z}`

Explanation

We have `f(x)=(1)/(8{x}^(2)-6{x}+1)`
Clearly `f(x)` is not defined if `8{x}^(2)-6{x}+1=0`
`implies (4{x}-1)(2{x}-1)=0`
`implies {x}=1//4 " or " 1//2`
`implies x=n+1//4 " or " x=n+1//2, " where " n in Z`
Hence domain of function is
`R-{x:x=n+1//4,n+1//2,n in Z}`