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Let P={(x,y)|x^(2)+y^(2)=1,x,yinR}. Then...

Let `P={(x,y)|x^(2)+y^(2)=1,x,yinR}`. Then, `P`, is

A

A. Reflexive

B

B. Symmetric

C

C. Transitive

D

D. Anti-symmetric

Text Solution

Verified by Experts

The correct Answer is:
B
Obviously, the relation is not transitive but it is symmetric, because `x^(2)+y^(2)=1 implies y^(2)+x^(2)=1`
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