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Let [x] represent the greatest integer less than or equal to `x` If [`sqrt(n^2+lambda)]=[n^2+1]+2` , where `lambda,n in N ,` then `lambda` can assume `(2n+4)d iffe r e n tv a l u s` `(2n+5)d iffe r e n tv a l u s` `(2n+3)d iffe r e n tv a l u s` `(2n+6)d iffe r e n tv a l u s`

A

`(2n+4)` different values

B

`(2n+5)` different values

C

`(2n+3)` different values

D

`(2n+6)` different values

Text Solution

Verified by Experts

The correct Answer is:
B

`[sqrt(n^(2)+1)]=n`
or `[sqrt(n^(2)+lambda)]=n+2`
or `n+2 le sqrt(n^(2)+lambda) lt n +3`
or `n^(2)+4 n+4 le n^(2)+lambda lt n^(2) +6n +9`
or `4n +4 le lambda lt 6n +9`
` :. 2n+5` values
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