If `f(x)` is a real=valued function defined as `f(x)=1N(1-sinx),` then the graph of `f(x)` is symmetric about the line `f(x)` is symmetric about the y-axis symmetric about the line `x=pi/2` symmetric about the origin

Options

A. A. symmetric about the line `x =pi`
B. symmetric about the y-axis
C. symmetric and the line ` x=(pi)/(2)`
D. symmetric about the origin

Answer

C

Explanation

`f((pi)/(2)-x)=In (1-cos x)`
` and f((pi)/(2)+x)=In(1-cosx)`
Thus, `f((pi)/(2)+x)=f((pi)/(2)-x)`
Thus f(x) is symmetrical about line `x=(pi)/(2).`