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The straight line y = x - 2 rotates abou...

The straight line `y = x - 2` rotates about a point where it cuts x-axis and become perpendicular on the straight line `ax + by + c = 0` then its equation is

A

`ax +by +20 = 0`

B

`ax - by - 2a = 0`

C

`bx +ay - 2b = 0`

D

`ay - bx +2b = 0`

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The correct Answer is:
D

Slopes of the line in the new position is bla, since it is perpendicular to the line `ax +by +c = 0` and it cuts the x-axis . Hence the required line passes through (2,0) and its slope is bla. The required is `y - 0 = (b)/(a) (x-2)` or `ay = bx - 2b`
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