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The breadth of a rectangle is 3cm less t...

The breadth of a rectangle is 3cm less than its length. If the area of the rectangle be 40 square cm. Find its perimeter.

A

`x = 1`

B

`x +y = 1`

C

`y = 9`

D

`x - 2y = 3`

Text Solution

Verified by Experts

The correct Answer is:
A, C

The intersection point of the given diagonals is `P -= ((3)/(2),5)`
Equation of angle bisectors of the diagonals are
`(y+8x -17)/(sqrt(65)) =+-(y-8x +7)/(sqrt(65))`
or `x =(3)/(2)` and `y = 5`
Let the length of BC be a and that of CD be b.
Then `tan =(a//2)/(b//2) =(a)/(b) =8`.
Also `ab = 8`
`rArr a = 8, b = 1`.
So equations of side are `y = 1, y = 9, x = 1` and `x = 2`
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