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The joint equation of pair of lines whic...

The joint equation of pair of lines which passes through origin and are perpendicular to the lines represented the equation `y^(2) +3xy -6x +5y - 14 = 0` will be

A

`y^(2) - 3xy = 0`

B

`3y^(2) - xy = 0`

C

`x^(2) - 3xy = 0`

D

`3x^(2) - xy = 0`

Text Solution

Verified by Experts

The correct Answer is:
C
Homogeneous part of the given equation is `y^(2) +3xy =0`, which represents straight lines `y =0` and `y+3x =0`. Now lines perpendicular to these lines are `x =0` and `x -3y =0`. So combined equation of above lines is
`x^(2) - 3xy =0`
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