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If 2x +3y = alpha, x -y = beta and kx +1...

If `2x +3y = alpha, x -y = beta` and `kx +15y = r` are 3 concurrent normal of parabola `y^(2) = lambda x` then value of k is (a) 3 (b) 4 (c) 5 (d) 7

A

3

B

4

C

5

D

7

Text Solution

Verified by Experts

The correct Answer is:
C
`t_(1)+t_(2)+t_(3) =0`
`rArr ((-2)/(3)) +1 + ((-k)/(15)) =0`
`rArr (k)/(15) = (1)/(3) rArr k = 5`
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