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If the centre, vertex and focus of a hyp...

If the centre, vertex and focus of a hyperbola be (0,0), (4,0) and (6,0) respectively, then the equation of the hyperbola is

A

`4x^(2) -5y^(2) = 8`

B

`4x^(2)-5y^(2) = 80`

C

`5x^(2)-4y^(2) =80`

D

`5x^(2)-4y^(2) =8`

Text Solution

Verified by Experts

The correct Answer is:
C
Centre (0,0), vertex (4,0)
`rArr a = 4` and focus (6,0)
`rArr ae = 6 rArr e = (3)/(2)`. Therefore `b = sqrt(20)`
Hence required equation is `(x^(2))/(16) -(y^(2))/(20) =1`
i.e., `5x^(2) - 4y^(2) = 80`
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