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The point (3tan (theta +60^(@)),2 tan(th...

The point `(3tan (theta +60^(@)),2 tan(theta +30^(@)))` lies on the conic, then its centre is `(theta` is the parameter)

A

`(-3sqrt(3),2sqrt(3))`

B

`(3sqrt(3),-2sqrt(3))`

C

`(-3sqrt(3),-2sqrt(3))`

D

(0,0)

Text Solution

Verified by Experts

The correct Answer is:
A
Let `(3 tan (theta + 60^(@)),2 tan (theta + 30^(@)) -= (h,k)`
`:. tan (theta + 60^(@)) = (h)/(3)` (1)
and `tan (theta + 30^(@)) = (k)/(2)` (2)
`tan 30^(@) = tan [(theta + 60^(@))- (theta + 30^(@))]`
`rArr (1)/(sqrt(3)) = (tan (theta+60^(@))-tan(theta+30^(@)))/(1+tan (theta+60^(@))tan (theta+30^(@)))`
`rArr (1)/(sqrt(3)) =((x)/(3)-(y)/(2))/(1+(xy)/(6))`
`rArr xy - 2sqrt(3)x + 3sqrt(3)y + 6 =0`
`rArr (x+3sqrt(3)) (y-2sqrt(3)) + 24 =0`
`rArr` center is `(-3sqrt(2),2sqrt(3))`
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