Find the equation of the curve whose par...

Find the equation of the curve whose parametric equation are `x=1+4costheta,y=2+3sintheta,theta in Rdot`

Verified by Experts

We have, `x=1+4 cos theta, y=2+3 sin theta`. Therefore , `((x-1)/(4))^(2)+((y-2)/(3))^(2)=1`
or `((x-1))/(16)+((y-2)^(2))/(9)=1` which is an ellipse.

Similar Questions

Explore conceptually related problems

Find the equation of the curve whose parametric equations are x=1+4costheta,y=2+3sintheta,theta in R .

Find the centre of the circle whose parametric equation is x= -1+2 cos theta , y= 3+2 sin theta .

Find the equation to the circle whose parametric equations are, x = (1)/(2)(1+5 cos theta), y = (1)/(2)(-2 + 5sin theta)

If theta be a variable parameter find the curve whose parametric equations are x=1/4(3-cosec^2theta)&y=2+cottheta

Find the centre of the circle whose parametric equations are x = - (1)/(2) (1 + 5 cos theta ) , y = (1)/(2) (-2 + 5 sin theta) .

Solve the equation 2cos^2theta+3sintheta=0

Find the vector equation of the plane whose cartesian from of equation is 3x-4y+2z=5

Find the equation to the locus represented by the parametric equations x=2t^(2)+t+1, y=t^(2)-t+1 .

The vertex of the parabola whose parametric equation is x=t^2-t+1,y=t^2+t+1; t in R , is

Find the equation of the curve whose slope at any point (x,y) is (-y) and which through the point (2,1)