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Find the equation of an ellipse whose...

Find the equation of an ellipse whose axes are the x-and y-axis and whose one focus is at (4,0) and eccentricity is 4/5.

Text Solution

Verified by Experts

The correct Answer is:
`(x^(2))/(25)+(y^(2))/(9)=1`
Here ae=4 and e=4/5. So, a=5
Now, `b^(2)=a^(2)(1-e^(2))`
or `b^(2)=25(1-(16)/(25))=9`
Hence, the equation of the ellipse be `(x^(2))/(25)+(y^(2))/(9)=1`
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