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The equation of the line passing through...

The equation of the line passing through the center and bisecting the chord `7x+y-1=0` of the ellipse `(x^2)/1+(y^2)/7=1` is

A

x=y

B

2x=y

C

x=2y

D

x+y=0

Text Solution

Verified by Experts

The correct Answer is:
A
Let (h,k) be the midpoint of the chord 7x+y-1=0. Then,
`(hx)/(1)+(ky)/(7)=(h^(2))/(1)+(k^(2))/(7)" "(1)`
and `7x+y=1 " "(2)`
represent the same straight line. Therefore,
`(h)/(7)=(k)/(7) or h=k`
Thus, the equation of the line joining (0,0) adn (h,k) is ty-x=0
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