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tan100^0+tan125^0+tan100^0tan125^0 is eq...

`tan100^0+tan125^0+tan100^0tan125^0` is equal to

A

0

B

`1/2`

C

`-1`

D

1

Text Solution

Verified by Experts

The correct Answer is:
D
`tan (100^(@)+125^(@))=(tan 100^(@)+tan 125^(@))/(1-tan100^(@)tan125^(@))`
`tan225^(@)=(tan100^(@)+tan125^(@))/(1-tan100^(@)Tan125^(@))`
i.e. `1=(tan 100^(@)+tan 125^(@))/(1-tan100^(@)tan125^(@))`
i.e. `tan 100^(@)+tan125^(@)+tan100^(@)tan 125^(@)=1`
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