If in parallelogram ABCD, diagonal vectors are `vec(AC)=2hati+3hatj+4hatk` and `vec(BD)=-6hati+7hatj-2hatk`, then find the adjacent side vectors `vec(AB) and vec(AD)`.

Explanation

Let `vec(AB) =veca and vec(AD)=vecb`. Then
`" "vec(AC)=veca+vecb and vec(BD)=vecb-veca`
`rArr" "vecb=(vec(AC)+vec(BD))/(2) and veca=(vec(AC)-vec(BD))/(2)`
`rArr" "vec(AB)=-2hati+35 +hatk and vec(AD)=4hati-2hatj+3hatk`