Find the direction cosines of the vector `hati+2hatj+3hatk`.

Explanation

Let `veca=hati+2hatj+3hatk`
`therefore" "|veca|=sqrt(1^(2)+2^(2)+3^(2))=sqrt(1+4+9)=sqrt(14)`
Hence, the direction cosines of `veca` are
`" "((1)/(sqrt(14)), (2)/(sqrt(14)), (3)/(sqrt(14)))`.