Solve `(x^2+3x+2)/(x^2-6x-7)=0.`

Answer

`x = -2`

Explanation

`(x^(2) _ 3x + 2)/(x^(2) - 6x - 7) = 0 or((x+ 1)(x+2))/((x-7)(x+ 1)) = 0` is solvable over R - {7, -1}
Hence, from given equation, x = -2, which is the only roots of the equation.