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Solve sqrt(x-2)(x^2-4x-5)=0....

Solve `sqrt(x-2)(x^2-4x-5)=0.`

Text Solution

Verified by Experts

The correct Answer is:
`x = 2 or 5`
Given equation is solvable for x`in [2,infty)`. Now
`sqrt(x - 2)(x^(2) - 4x - 5) = 0`
or `sqrt(x - 2)(x - 5)(x - 1) = 0`
lt `rArr x = 2 or 5 (x ne -1, as x in [2, infty)`
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