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Find the range of f(x)=x^2-x-3....

Find the range of `f(x)=x^2-x-3.`

Text Solution

Verified by Experts

The correct Answer is:
`[-13//4, infty)`
`f(x) = x^(2) - x - 3 (x - (1)/(2))^(2) - (1)/(4) - 3 = (x - (1)/(2))^(2)-(13)/(4)`
` (x - (1)/(2))^(2 )ge 0, AA x in` R
` (x - (1)/(2))^(2 )-(13)/(4)ge (-13)/(4), AA x in`R
Hence, the range is `[13//4. infty)`.
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