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The quadratic x^2+a x=b+1=0 has roots wh...

The quadratic `x^2+a x=b+1=0` has roots which are positive integers, then `(a^2+b^2)` can be equal to `50` b. `37` c. `61` d. `19`

A

50

B

37

C

61

D

19

Text Solution

Verified by Experts

The correct Answer is:
1

`x^(2) + ax + b + 1 = 0` has positive integral roots `alpha and beta`.
Now, `(alpha + beta) = -a and alphabeta = b + 1`
`rArr (alpha + beta)^(2) + (alphabeta - 1)^(2) = a^(2) + b^(2)`
`rArr a^(2) +b^(2) = (alpha^(2) + 1)(beta^(2) + 1).`
`rArr a^(2) + b^(2)` can be equal to 50 (since other options have prime numbers)
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