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For x^2-(a+3)|x|+4=0 to have real soluti...

For `x^2-(a+3)|x|+4=0` to have real solutions, the range of `a` is a. `(-oo,-7]uu[1,oo)` b. `(-3,oo)` c. `(-oo,-7)` d. `[1,oo)`

A

`(-infty, - 7][1, infty)`

B

`(-3, infty)`

C

`(-infty, -7]`

D

`[ 1 , infty)`

Text Solution

Verified by Experts

The correct Answer is:
4
` a = (x^(2) + 4)/(|x|) - 3 = |x| + (4)/(|x|)- 3 = (sqrt(|x|) - (2)/(sqrt(|x|)))^(2) + 1 `
`rArr a ge 1` .
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