If `ax^(2)+(b-c)x+a-b-c=0` has unequal real roots for all `c epsilonR`, then

Options

A. ` b lt 0 lt a `
B. `a lt 0 lt b `
C. `b lt alt 0 `
D. `b gt a gt 0 `

Answer

3,4

Explanation

We have,
` D = (b - c)^(2) - 4a(a - b - c) gt 0 `
or ` b^(2) + c^(2) - 2bc - 4a^(2) + 4ab + 4ac gt 0 `
` or c^(2) + (4a - 2b) c - 4a^(2) + 4ab + b^(2) gt 0 ` for all ` c in ` R
Discriminant of the above expression in c must be negative
Hence,
` 1(4a = 2b)^(2) - 4 (-4a^(2) + 4ab + b^(2)) lt 0 `
or ` 4a^(2) - 4ab + b ^(2) + 4a^(2) - 4ab - b^(2) lt 0 `
or ` a (a - b) lt 0 `
`rArr a lt 0 and a - b gt 0 or a gt 0 and a - b lt 0 `
`rArr b lt a lt 0 or b gt a gt 0 ` .