Find the area enclosed between the curves: `y = log_e (x + e) , x = log_e (1/y)` & the x-axis.

The area enclosed between the curves y=(log)_e(x+e),x=(log)_e(1/y), and the x-axis is 2s qdotu n i t s (b) 1s qdotu n i t s 4s qdotu n i t s (d) none of these

The area enclosed between the curve y = log_e (x +e ) and the coordinate axes is

The area enclosed between the curve y = log_e (x +e ) and the coordinate axes is

Plot the curve y=log_(e)(-x)

The area encosed between the curves y=log_(e)(x+e),y=e^(x) and the X-axis is

The area enclosed between the curve y=log_e(x+e) and the coordinate axes is :

The area enclosed between the curve y=log_(e)(x+e) and the coordinate axes is