Find the sumsum(0leiltjlen)1....

Find the `sumsum_(0leiltjlen)1`.

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`underset(0leiltjlen)(sumsum1)=(sum_(i=1)^(n)sum_(j=1)^(n)1-sum_(i=j)sum1)/2`
`=((sum_(j=1)^(n)1)(sum_(j=1)^(n)1)-sum_(j=1)^(n))/2`
`=(n^(2)-n)/2`
`=(n(n-1))/2`

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CENGAGE PUBLICATION-PROGRESSION AND SERIES-ILLUSTRATION 5.93

Find the sumsum(0leiltjlen)1.
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