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The value of sum(i-1)^nsum(j=1)^isum(k=1...

The value of `sum_(i-1)^nsum_(j=1)^isum_(k=1)^j1=220 ,` then the value of `n` equals `11` b. `12` c.10 d. 9

A

11

B

12

C

10

D

9

Text Solution

Verified by Experts

The correct Answer is:
C
The sum equals `(n(n+1)(n+2))/6=220`
Which is true for n=10
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