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If tn denotes the nth term of the series...

If `t_n` denotes the nth term of the series 2+3+6+11+18+….. Then `t_50` is

A

`49^2-1`

B

`49^2`

C

`50^2+1`

D

`49^2+2`

Text Solution

Verified by Experts

The correct Answer is:
D
`2+3+6+11+18+…`
`=(0^(2)+2)+(1^(2)+2)+(2^(2)+2)+(3^(2)+2)+…`
Hence, `t_(50)=49^(2)+2`.
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