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Find the number of zeros at the end of 130.

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The number of zeros at the end of 130! Is equal to the exponent of 10 in 130. Now, exponent of 10 is equal to exponent of 5 as exponent of 2 is higher than exponent of 5. Now, exponent of 5 is
`[(130)/(5)]+[(130)/(5^(2))]+[(130)/(5^(3))]=26+5+1=32`
Also, exponent of 10 is 32, hence, there are 32 zeros at the end of 130. It should be noted that exponent of 2 is
`[(130)/(2)]+[(130)/(2^(2))]+[(130)/(2^(3))]+[(130)/(2^(4))]+[(130)/(2^(5))]+[(130)/(2^(6))]+[(130)/(2^(7))]`
=65+32+16+8+4+2+1=128
Hence, exponent of 10 is equal to exponent of 5.
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