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Find the total number of nine-digit numb...

Find the total number of nine-digit numbers that can be formed using the digits 2, 2, 3, 3, 5, 5, 8, 8, 8 so that the odd digit occupy the even places.

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Odd digits 3,3,5,5 occupy four even places in `4!//(2!2!)=6` ways. Rest five digits 2,2,8,8,8 occupy rest five places in `5!//(2!3!)=10` ways. Hence, the total number of ways is `6xx10=60`.
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