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A library has a copies of one book, b...

A library has `a` copies of one book, `b` copies each of two books, `c` copies each of three books, a single copy of `d` books. The total number of ways in which these books can be arranged in a shelf is equal to a. `((a+2b+3c+d)!)/(a !(b !)^2(c !)^3)` b. `((a+2b+3c+d)!)/(a !(2b !)^(c !)^3)` c. `((a+b+3c+d)!)/((c !)^3)` d. `((a+2b+3c+d)!)/(a !(2b !)^(c !)^)`

Text Solution

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The correct Answer is:
`((a+2b+3c+d))/(a!b!b!c!c!c!)`
Total number of books =a+2b+3c+d
Total number of ways in which these books can be arranged in a shelf
`=((a+2b+3c+d)!)/(a!b!c!c!c!)`
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