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Find the number of three-digit numbers f...

Find the number of three-digit numbers formed by using digits 1,2,3,4,6,7,8,9 without repetition such that sum of digits of the numbers formed is even.

Text Solution

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The correct Answer is:
168
Sum of digits is even if all the digits are even or one is digit even other two odd.
So, number of ways of selections are `(.^(4)C_(3)+ .^(4)C_(1)xx .^(3)C_(2))=16`
Hence number of words `=16xx3! =168`
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