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Find the number of odd proper divisors o...

Find the number of odd proper divisors of `3^pxx6^mxx21^ndot`

Text Solution

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The correct Answer is:
(p+m+n+1)(n+1)-1
`3^(p)6^(m)21^(n)=2^(m)3^(p+m+n)7^(n)`
Therefore, the required number of proper divisors is equal to the number of selections of any number of 3's and 7's `[because` for odd divisors 2 must not be selected ] and is given by (p+m+n+1) (n+1)-1.
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