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Find the number of ways in which four di...

Find the number of ways in which four distinct balls can be kept into two identical boxes so that no box remains empty.

Text Solution

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The correct Answer is:
7
4 distinct balls can be divided into two nonempty groups as 1,3 or 2,2
Sine boxes are identical, number of ways of division and distibution are same
`therefore` Number of ways `=(4!)/(1!3!)+(4)/(2!2!2!)=4+3=7`.
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