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If f(1)=3, f'(1) = 2, f''(1)=4, then (...

If `f(1)=3, f'(1) = 2, f''(1)=4`, then `(f^-)''(3)=` (where `f^-1=`inverse of `y = f(x))`

A

1

B

`-(1)/(2)`

C

`-2`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
We know that `(d^(2)x)/(dy^(2))=((-d^(2)y)/(dx^(2)))/(((dy)/(dx))^(3))=(-4)/(8)=-(1)/(2)`
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