The function `y=(2x-1)/(x-2),(x!=2)` is its own inverse decrease at all values of `x` in the domain has a graph entirely above the `x-a xi s` is unbounded

Options

A. is its own inverse
B. decreases at all values of x in the domain
C. has a graph intirely above the x axis
D. is unbounded

Answer

1,2,4

Explanation

`y=(2x-1)/(x-2)`
`(dy)/(dx)=(2(x-2)-(2x-1))/(x-2)^(2)=(-3)/(2)^(2)lt0 forall x ne 2 `
`y=(2x-1)/(x-2) or x=(2y-1)/(y-2)`
`therefore f^(-1)(x)=(2x-1)/(x-2)`
Thus f(X) is its own inverse