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Let f(x) =ax^(2) + bx + c and f(-1) lt 1...

Let `f(x) =ax^(2) + bx + c` and `f(-1) lt 1, f(1) gt -1, f(3) lt -4` and `a ne 0`, then

A

(a) a>0

B

(b) a<0

C

(c) Sign of a can't be determined

D

(a) none of the above

Text Solution

Verified by Experts

The correct Answer is:
2,3
Since g(x) is increasing and f(x) is decreasing
`g(x+1)gtg(x-1)and f(x+1)ltf(x-1)`
or `f{g(x+1)}ltf{(g(x-1)}`
and `g{f(x+1)}ltg{f(x-1)}`
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