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Given f(x)=4-(1/2-x)^(2/3),g(x)={("tan"[...

Given `f(x)=4-(1/2-x)^(2/3),g(x)={("tan"[x])/x ,x!=0 1,x=0` `h(x)={x},k(x)=5^((log)_2(x+3))` Then in [0,1], lagranges mean value theorem is not applicable to (where [.] and {.} represents the greatest integer functions and fractional part functions, respectively). `f` (b) `g` (c) `k` (d) `h`

A

f

B

g

C

k

D

h

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Given f(x)=4-(1/2-x)^(2/3),g(x)={("tan"[x])/x ,x!=0 1,x=0 , h(x)={x}, k(x)=5^((log)_2(x+3)). Then in [0,1], lagranges mean value theorem is not applicable to (a) f (b) g (c) k (d) h (where [.] and {.} represents the greatest integer functions and fractional part functions, respectively).

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f:(2,3)->(0,1) defined by f(x)=x-[x] ,where [dot] represents the greatest integer function.

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